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Combinations (Medium)

AMC 10/12 mid (≈Q9–16) — multi-step.

Combinations: core idea

Identities.

Example problem: hint and answer

How many ways can a 44-person committee be chosen from 1010 people?

Hint: Split restricted selections into independent choices. Answer: 210.

Practice (9 problems — type your answers)

  • 1. How many diagonals does a decagon have?

  • 2. How many ways can 33 red balls be chosen from 77 red balls?

  • 3. How many 55-card hands can be chosen from 1010 cards?

  • 4. How many ways can 33 pizza toppings be chosen from 88?

  • 5. A class has 66 boys and 55 girls. How many 33-person groups have exactly two girls?

  • 6. How many ways can 44 vertices of a hexagon be selected?

  • 7. How many ways can 22 prizes be given to 66 people if the prizes are identical?

  • 8. How many ways can 55 questions be selected from 1212?

  • 9. How many ways can a team of 44 be selected from 99 people if one person must be included?

Combinations Practice Problems — Medium